PROC IML;
rG={ 1.00 0.433 -0.401, 0.433 1.00 0.529, -0.401 0.529 1.00};
rP={ 1.00 0.416 0.058, 0.416 1.00 0.104, 0.058 0.104 1.00};
sP={4.17, 1.24, 23.58}; H2={0.210, 0.378, 0.157}; sG=SQRT(sP#H2#sP);
V0=Hdir(sP, I(3))* rP * Hdir(sP, I(3)); G0=Hdir(sG, I(3))* rG * Hdir(sG, I(3)); V00=V0; G00=G0;
W= { 3.97, -6.36, 1};
INV_V0= INV(V0); b = INV(V0)*G0*w; PRINT b;
G0w=G0*w; PRINT G0w; V_I = b`*V0*b; PRINT V_I; V_H = w`*G0*w; PRINT V_H; R_IH = SQRT (V_I/V_H); PRINT R_IH;
DLT_A = G0*b*(1 / SQRT(V_I) ); PRINT DLT_A;
DUMY=J(2,2,0);k2={0,0}; PRINT DUMY k2;
y=G0w//k2; PRINT y; G1=G0(| ,1|); PRINT G1; G2=G0(| ,2|); PRINT G2; G02=G1||G2; PRINT G02;
C1=V0||G02; C2=G02`||DUMY; C =C1//C2; PRINT C;
INV_C=INV(C); b0=INV_C*y; PRINT INV_C;PRINT b0; V_I = b0[1:3,]`*V00*b0[1:3,]; PRINT V_I; DLT_A =G0*b0[1:3,]*(1 / SQRT(V_I) ); PRINT DLT_A;
kc=G0*b; yc=G0w//kc; PRINT kc yc;
O22=J(3,3,0); PRINT O22; CC1=V0||G0; CC2=G0||O22; CC =CC1//CC2; PRINT CC;
INV_CC=INV(CC); b02=INV_CC*yc; PRINT INV_CC;PRINT b02;
ratio={0, 0, 3 }; kp=ratio#kc; PRINT ratio kc kp; yp=G0w//kp; PRINT G0w; PRINT kp yp;
bd1=INV_CC*yp; bd2=INV(G0)*kp; PRINT INV_CC;PRINT bd1 bd2; bd3=bd2*(0.099/ 6.1628537); print bd3; * 解2,解3 成比例非唯一解;
RUN;